1. Asked: December 7, 2021In:

    Newton of motion

    @olago
    @olago Begginer

    Initial k.e = ½*20*4*4 = 160j Final k.e = 2*160 = 320j Final Velocity = √(2*320)÷20 = √32 m/s = 5.66m/s Ft = m(v-u) t = 20(√32-4)÷5 t = 6.64s

    Initial k.e = ½*20*4*4
    = 160j

    Final k.e = 2*160
    = 320j

    Final Velocity = √(2*320)÷20
    = √32 m/s
    = 5.66m/s

    Ft = m(v-u)

    t = 20(√32-4)÷5
    t = 6.64s

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