Sign Up Sign Up

Don't forget to check your email for the activation link. Otherwise, you will not be able to login until you activate your account.

Browse

Captcha Click on image to update the captcha.

Have an account? Sign In Now

Sign In Sign In

Use your email and password to login.

Captcha Click on image to update the captcha.

Forgot Password?

Don't have account, Sign Up Here

Forgot Password Forgot Password

Reset your password.

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Captcha Click on image to update the captcha.

Have an account? Sign In Now

You must login to ask a question.

Captcha Click on image to update the captcha.

Forgot Password?

Need An Account, Sign Up Here

You must login to ask a question.

Captcha Click on image to update the captcha.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

Teachers Of Physics

Teachers Of Physics Logo Teachers Of Physics Logo

Teachers Of Physics Navigation

  • Home
  • Categories
  • Questions
    • New Questions
    • Trending Questions
    • Top Questions
    • Hot Questions
  • Joint Examinations
  • KCSE MS
    • 2020
  • Polls
  • Users
  • Badges
  • Cloud Storage
  • Solved Topical Questions
  • Need Help?
Search
Ask A Question

Mobile menu

Close
Ask A Question
  • Meet The Team
  • Blog
  • About Us
  • Contact Us

@olago

Begginer
Ask @olago
342 Visits
0 Followers
0 Questions
Home/ @olago/Answers
  • About
  • Questions
  • Polls
  • Answers
  • Best Answers
  • Followed
  • Favorites
  • Groups
  1. Asked: December 7, 2021In: Mechanical Physics

    Newton of motion

    @olago
    Best Answer
    @olago Begginer
    Added an answer on April 15, 2022 at 12:20 pm

    Initial k.e = ½*20*4*4 = 160j Final k.e = 2*160 = 320j Final Velocity = √(2*320)÷20 = √32 m/s = 5.66m/s Ft = m(v-u) t = 20(√32-4)÷5 t = 6.64s

    Initial k.e = ½*20*4*4
    = 160j

    Final k.e = 2*160
    = 320j

    Final Velocity = √(2*320)÷20
    = √32 m/s
    = 5.66m/s

    Ft = m(v-u)

    t = 20(√32-4)÷5
    t = 6.64s

    See less
      • 0
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
  2. Asked: January 19, 2022In: Electricity and Magnetism

    Factors affecting capacitance

    @olago
    @olago Begginer
    Added an answer on April 15, 2022 at 12:11 pm

    1. Area of overlap. 2. Distance of separation. 3. The nature of dielectric material.

    1. Area of overlap.
    2. Distance of separation.
    3. The nature of dielectric material.

    See less
      • 1
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
  3. Asked: September 16, 2020In: Mechanical Physics

    A ball thrown vertically from a moving vehicle

    @olago
    @olago Begginer
    Added an answer on April 13, 2022 at 7:06 am

    The ball will fall into the open moving car. This is because the constant velocity of the open moving car is equivalent to the velocity with which the projectile moves.

    The ball will fall into the open moving car. This is because the constant velocity of the open moving car is equivalent to the velocity with which the projectile moves.

    See less
      • 0
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp

Sidebar

Q&A Mobile Application

Explore

  • Home
  • About Us
  • Blog
  • Contact Us

Copyright © 2023 Teachers of Physics. All Rights Reserved
Made in Kenya by LION.