the initial velocity of a body 20kg is 4m/s. how long would a constant force of 5N act on the body to double its kinetic energy
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Initial k.e = ½*20*4*4
= 160j
Final k.e = 2*160
= 320j
Final Velocity = √(2*320)÷20
= √32 m/s
= 5.66m/s
Ft = m(v-u)
t = 20(√32-4)÷5
t = 6.64s